**Publisher:** Edward E. Rochon

**Publication Date:** May 13, 2018

**ISBN:** 9781370446346

**Binding:** Kobo eBook

**Availability:**
eBook

The ratio of the unit square sides (s) to the diagonal is: v2/1. We try to find the commensurable value that fits into both numerator and denominator. First, v2/1 = v2. We see that (s) is within the root and do not need the denominator (s). We note that all fractions are portions of the unit value (1). We note that all number bases are commensurable in fractional parts to (1). The first power of 10 is commensurable by ten (1/10th)'s. The (1/100th) is commensurable into the 10th's positions, etc., for all reciprocal powers of the mantissa or fractional positions. This is absolutely certain by the definition of base positional notation. That being the case, how could not all elements of the mantissa not be commensurable to each other and the unit whole number to the left of the decimal point? They are. and (1) = (s) and the proof is done. If you suppose some trick of positional notation, we know that all fractions are ratios of whole ...